2D的芳綸絲理論直徑是多少

V柱=ЛH柱R柱^2V錐=(ЛH錐R錐^2)3V柱/V錐=3H柱R柱^2/(H錐R錐^2)第一題3*2h*(2d/2)*(2d/2)/[h*(d/2)*(d/2)]=24:1第二題直徑比1:3既是半徑比為1:33*h*r*r/(2h*3r*3r)=1:6